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Greek Gymnasium Grade 2 · 45 minutes · 40 marks

Physics · Greek Gymnasium Grade 2: Forces and pressure

Forces · Pressure

Original pilot material — human educator review pending Written specifically for YourFavTeacher with AI assistance, without copying past-paper prompts. Technical and numerical checks do not replace review by a human educator. It is not an official paper or endorsed by an examination body.

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Time remaining: 45:00

Before you start

  • A complete original revision assessment of the two listed units only — not a full Panhellenic mock paper or whole-year assessment.
  • Timing is indicative. Show method, calculation and checking. In physics, include units and direction where required.
  • The indicative rubric accepts equivalent correct methods. Do not penalise the same arithmetic error again when subsequent working is consistent. This is not a diagnostic instrument or official grade.

Materials: Pencil, paper and ruler. Leave π exact where needed. · The numerical data do not require a calculator. This is not an official examination rule.

ForcesPressure
Go to questions

Questions and marks

Work on paper first. Solutions stay closed until you choose to reveal them. Marks are for self-assessment, not automated or official grading.

1. Question 1

5 marks

A box experiences 14 N rightwards and 6 N leftwards. Find the resultant.

Worked solution and marking guide — Question 1
  1. Take rightwards as positive.

  2. ΣF=14−6=8 N

  3. Keep SI units and check the sign.

8 N →

Mark allocation

  • Take rightwards as positive. — 1 marks
  • ΣF=14−6=8 N — 2 marks
  • Keep SI units and check the sign. — 2 marks

2. Question 2

5 marks

A stationary box experiences 7 N rightwards. What horizontal force is needed for equilibrium?

Worked solution and marking guide — Question 2
  1. Equilibrium requires zero resultant.

  2. 7+F=0 ⇒ F=−7 N

  3. The negative sign denotes leftwards.

7 N ←

Mark allocation

  • Equilibrium requires zero resultant. — 1 marks
  • 7+F=0 ⇒ F=−7 N — 2 marks
  • The negative sign denotes leftwards. — 2 marks

3. Question 3

5 marks

A body moves in a straight line at constant velocity. Is its resultant force or its velocity zero?

Worked solution and marking guide — Question 3
  1. Velocity does not change, but is not necessarily zero.

  2. Apply Newton's first law in an inertial reference frame.

  3. Balanced forces are compatible with uniform motion.

Zero resultant force, not necessarily zero velocity.

Mark allocation

  • Velocity does not change, but is not necessarily zero. — 1 marks
  • Apply Newton's first law in an inertial reference frame. — 2 marks
  • Balanced forces are compatible with uniform motion. — 2 marks

4. Question 4

5 marks

A body experiences 7 N and 6 N rightwards, and 13 N leftwards. Calculate the resultant.

Worked solution and marking guide — Question 4
  1. Add all forces algebraically along the same axis.

  2. ΣF=7+6−13=0 N

  3. We cannot infer rest without knowing the initial velocity.

0 N

Mark allocation

  • Add all forces algebraically along the same axis. — 1 marks
  • ΣF=7+6−13=0 N — 2 marks
  • We cannot infer rest without knowing the initial velocity. — 2 marks

5. Question 5

5 marks

A normal force of 140 N acts over 0.02 m². Find the pressure.

Worked solution and marking guide — Question 5
  1. Use p=Fnormal/A with area in m².

  2. p=140/0.02=7000 Pa

  3. Pa equals N/m², not N.

7000 Pa

Mark allocation

  • Use p=Fnormal/A with area in m². — 1 marks
  • p=140/0.02=7000 Pa — 2 marks
  • Pa equals N/m², not N. — 2 marks

6. Question 6

5 marks

A pressure of 7000 Pa acts over 0.03 m². Find the normal force.

Worked solution and marking guide — Question 6
  1. Rearrange the definition: F=pA.

  2. F=7000·0.03=210 N

  3. Keep SI units and check the sign.

210 N

Mark allocation

  • Rearrange the definition: F=pA. — 1 marks
  • F=7000·0.03=210 N — 2 marks
  • Keep SI units and check the sign. — 2 marks

7. Question 7

5 marks

At depth 6 m in water, atmospheric pressure is 100000 Pa. Find total pressure with ρ=1000 kg/m³, g=10 m/s².

Worked solution and marking guide — Question 7
  1. Total pressure includes atmospheric and hydrostatic contributions.

  2. p=100000+1000·10·6=160000 Pa

  3. Total pressure exceeds atmospheric pressure.

160000 Pa

Mark allocation

  • Total pressure includes atmospheric and hydrostatic contributions. — 1 marks
  • p=100000+1000·10·6=160000 Pa — 2 marks
  • Total pressure exceeds atmospheric pressure. — 2 marks

8. Question 8

5 marks

Convert 7 cm² to m² before using the pressure formula.

Worked solution and marking guide — Question 8
  1. Square the length conversion factor.

  2. 1 cm²=(0.01 m)²=0.0001 m²; 7 cm²=7/10000 m²

  3. Do not divide by only 100.

0.0007 m²

Mark allocation

  • Square the length conversion factor. — 1 marks
  • 1 cm²=(0.01 m)²=0.0001 m²; 7 cm²=7/10000 m² — 2 marks
  • Do not divide by only 100. — 2 marks

Provenance and scope

Original authorship for YourFavTeacher with AI assistance.

Official sources were checked only for topic and level reference. No specific past-paper prompts, diagrams or solutions were copied or adapted. No external endorsement or licence to republish third-party papers is claimed.

Edition: 2026-09-06

  • Digital School — Physics, Gymnasium Grade 2 ↗ (new tab)

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