Learning objectives
- I can explain and apply: Substitution and elimination.
- I can explain and apply: Graphical interpretation.
- I can explain and apply: Modelling and verification.
Greek Gymnasium Grade 3 / Mathematics / Two-unit revision pilot
Systems of linear equations: structured theory, worked examples, answered practice, and a mastery checklist for Greek Gymnasium Grade 3.
CHAPTER PLAN
Follow the steps in order or jump directly to the part you need.
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Estimated active study time
156 minutes
Objectives, key ideas, and structured theory.
Open →Worked examples that explain every step.
Open →Graded tasks with hints and answer guidance.
Open →Assignments from core work to challenge.
Open →A timed, marked test with solution guidance.
Open →Progress is stored only in this browser and does not require AI credits.
Unit
The essential chapter ideas in a clear sequence before practice.
A system's solution is an ordered pair satisfying both equations simultaneously. Each equation represents a line: one intersection gives one solution, distinct parallel lines give none, and coincident lines give infinitely many.
For substitution, isolate one unknown and replace it with the complete equivalent expression in brackets. For elimination, scale entire equations so one unknown has opposite coefficients, then add.
In a word problem, define what each unknown counts and write the two constraints separately. After solving, check units, non-negativity and integer values when counting objects.
Written specifically for YourFavTeacher with AI assistance, without copying past-paper prompts. Technical and numerical checks do not replace review by a human educator. It is not an official paper or endorsed by an examination body.
Mathematics
Follow the method step by step and check why every step is valid.
Solve x+y=11, x−y=1.
x=6, y=5
How many solutions does x+y=6, 2x+2y=12 have? Give a general form.
Infinitely many: (x, 6−x), x∈ℝ.
The pair (6,5) satisfies x+y=11. Is that enough to solve x−y=0 as well?
No: it does not satisfy the second equation.
Systems of linear equations
Eight graded tasks from core fluency to exam-style application. Work independently before opening a hint or answer.
Solve x+y=5, x−y=1.
Add the equations to eliminate y.
Add the equations to eliminate y. 2x=6 ⇒ x=3; y=5−3=2 Check the pair in both equations. x=3, y=2
Solve y=2x−3, x+y=6.
Substitute the first expression for y into the second equation.
Substitute the first expression for y into the second equation. x+2x−3=6 ⇒ 3x=9 ⇒ x=3; y=3 Both sides of the second equation equal 6. x=3, y=3
Two ticket types cost €2 and €3. 5 tickets produced €12. Find how many of each type were sold.
Let x count €2 tickets and y count €3 tickets.
Let x count €2 tickets and y count €3 tickets. x+y=5; 2x+3y=12; 2x+2y=10; y=12−10=2; x=5−2=3 We subtracted twice the first equation from the second. The counts are non-negative integers and reproduce the total revenue. 3 × 2€, 2 × 3€
Does x+y=3, 2x+2y=7 have a solution?
Double the first equation.
Double the first equation. 2x+2y=6 The second demands a different total, 7, for the same expression. Inconsistent system: no solution.
How many solutions does x+y=3, 2x+2y=6 have? Give a general form.
The second equation is twice the first.
The second equation is twice the first. It adds no independent constraint. y=3−x Infinitely many: (x, 3−x), x∈ℝ.
Solve 2x+y=8, x+2y=7.
Double the second equation and subtract the first.
Double the second equation and subtract the first. 3y=6 ⇒ y=2; x=3 Check: 2·3+2=8 and 3+2·2=7. x=3, y=2
The lines y=x+2 and y=−x+8 intersect. Find the intersection.
At the intersection the two expressions for y are equal.
At the intersection the two expressions for y are equal. x+2=−x+8 ⇒ 2x=6 ⇒ x=3; y=5 The point must lie on both lines. (3, 5)
The pair (3,2) satisfies x+y=5. Is that enough to solve x−y=0 as well?
A system solution must satisfy every equation simultaneously.
A system solution must satisfy every equation simultaneously. 3−2=1≠0 Reject the pair even though it satisfies the first equation. No: it does not satisfy the second equation.
Systems of linear equations
Six distinct assignments from core fluency to challenge, each with an estimated time, hint, and answer guide.
Solve x+y=7, x−y=1.
Add the equations to eliminate y.
Add the equations to eliminate y. 2x=8 ⇒ x=4; y=7−4=3 Check the pair in both equations. x=4, y=3
Solve y=2x−4, x+y=8.
Substitute the first expression for y into the second equation.
Substitute the first expression for y into the second equation. x+2x−4=8 ⇒ 3x=12 ⇒ x=4; y=4 Both sides of the second equation equal 8. x=4, y=4
Two ticket types cost €2 and €3. 7 tickets produced €17. Find how many of each type were sold.
Let x count €2 tickets and y count €3 tickets.
Let x count €2 tickets and y count €3 tickets. x+y=7; 2x+3y=17; 2x+2y=14; y=17−14=3; x=7−3=4 We subtracted twice the first equation from the second. The counts are non-negative integers and reproduce the total revenue. 4 × 2€, 3 × 3€
Does x+y=4, 2x+2y=9 have a solution?
Double the first equation.
Double the first equation. 2x+2y=8 The second demands a different total, 9, for the same expression. Inconsistent system: no solution.
How many solutions does x+y=4, 2x+2y=8 have? Give a general form.
The second equation is twice the first.
The second equation is twice the first. It adds no independent constraint. y=4−x Infinitely many: (x, 4−x), x∈ℝ.
Solve 2x+y=11, x+2y=10.
Double the second equation and subtract the first.
Double the second equation and subtract the first. 3y=9 ⇒ y=3; x=4 Check: 2·4+3=11 and 4+2·3=10. x=4, y=3
45 minutes / 40 marks
A timed, full-mark self-assessment with model-answer guidance.
Show working, units and a final check. Equivalent correct methods are accepted. Timing is a revision guide, not official examination conditions.
1. Solve x+y=9, x−y=1.
5 marksAdd the equations to eliminate y. 2x=10 ⇒ x=5; y=9−5=4 Check the pair in both equations. x=5, y=4
2. Solve y=2x−5, x+y=10.
5 marksSubstitute the first expression for y into the second equation. x+2x−5=10 ⇒ 3x=15 ⇒ x=5; y=5 Both sides of the second equation equal 10. x=5, y=5
3. Two ticket types cost €2 and €3. 9 tickets produced €22. Find how many of each type were sold.
5 marksLet x count €2 tickets and y count €3 tickets. x+y=9; 2x+3y=22; 2x+2y=18; y=22−18=4; x=9−4=5 We subtracted twice the first equation from the second. The counts are non-negative integers and reproduce the total revenue. 5 × 2€, 4 × 3€
4. Does x+y=5, 2x+2y=11 have a solution?
5 marksDouble the first equation. 2x+2y=10 The second demands a different total, 11, for the same expression. Inconsistent system: no solution.
5. How many solutions does x+y=5, 2x+2y=10 have? Give a general form.
5 marksThe second equation is twice the first. It adds no independent constraint. y=5−x Infinitely many: (x, 5−x), x∈ℝ.
6. Solve 2x+y=14, x+2y=13.
5 marksDouble the second equation and subtract the first. 3y=12 ⇒ y=4; x=5 Check: 2·5+4=14 and 5+2·4=13. x=5, y=4
7. The lines y=x+4 and y=−x+14 intersect. Find the intersection.
5 marksAt the intersection the two expressions for y are equal. x+4=−x+14 ⇒ 2x=10 ⇒ x=5; y=9 The point must lie on both lines. (5, 9)
8. The pair (5,4) satisfies x+y=9. Is that enough to solve x−y=0 as well?
5 marksA system solution must satisfy every equation simultaneously. 5−4=1≠0 Reject the pair even though it satisfies the first equation. No: it does not satisfy the second equation.
Unit
Curriculum reference sources. Always confirm the teaching sequence with the school and tutor.
Mathematics
A bridge year into Lyceum: students need confidence in algebraic manipulation and basic proof thinking.
The structure follows the official textbook layout and is used to organise study.
The areas that usually create mistakes or need extra revision.
Where to start: textbook, daily material, PDFs, videos, and worked examples.
Targeted practice before full tests so coverage is clear.
How to measure progress in this chapter and when it enters a cumulative mock.
What to do after finishing the chapter and how it connects to the next unit.
Note: for the official examinable syllabus of each school year, always confirm with the school, tutor, and current Ministry/IEP announcements.